Optimal. Leaf size=88 \[ \frac{\sqrt{1+i \tan (e+f x)} F_1\left (n+1;\frac{3}{2},1;n+2;-i \tan (e+f x),i \tan (e+f x)\right ) (d \tan (e+f x))^{n+1}}{d f (n+1) \sqrt{a+i a \tan (e+f x)}} \]
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Rubi [A] time = 0.12434, antiderivative size = 88, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.107, Rules used = {3564, 135, 133} \[ \frac{\sqrt{1+i \tan (e+f x)} F_1\left (n+1;\frac{3}{2},1;n+2;-i \tan (e+f x),i \tan (e+f x)\right ) (d \tan (e+f x))^{n+1}}{d f (n+1) \sqrt{a+i a \tan (e+f x)}} \]
Antiderivative was successfully verified.
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Rule 3564
Rule 135
Rule 133
Rubi steps
\begin{align*} \int \frac{(d \tan (e+f x))^n}{\sqrt{a+i a \tan (e+f x)}} \, dx &=\frac{\left (i a^2\right ) \operatorname{Subst}\left (\int \frac{\left (-\frac{i d x}{a}\right )^n}{(a+x)^{3/2} \left (-a^2+a x\right )} \, dx,x,i a \tan (e+f x)\right )}{f}\\ &=\frac{\left (i a \sqrt{1+i \tan (e+f x)}\right ) \operatorname{Subst}\left (\int \frac{\left (-\frac{i d x}{a}\right )^n}{\left (1+\frac{x}{a}\right )^{3/2} \left (-a^2+a x\right )} \, dx,x,i a \tan (e+f x)\right )}{f \sqrt{a+i a \tan (e+f x)}}\\ &=\frac{F_1\left (1+n;\frac{3}{2},1;2+n;-i \tan (e+f x),i \tan (e+f x)\right ) \sqrt{1+i \tan (e+f x)} (d \tan (e+f x))^{1+n}}{d f (1+n) \sqrt{a+i a \tan (e+f x)}}\\ \end{align*}
Mathematica [F] time = 180.002, size = 0, normalized size = 0. \[ \text{\$Aborted} \]
Verification is Not applicable to the result.
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Maple [F] time = 0.397, size = 0, normalized size = 0. \begin{align*} \int{ \left ( d\tan \left ( fx+e \right ) \right ) ^{n}{\frac{1}{\sqrt{a+ia\tan \left ( fx+e \right ) }}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (d \tan \left (f x + e\right )\right )^{n}}{\sqrt{i \, a \tan \left (f x + e\right ) + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{2} \left (\frac{-i \, d e^{\left (2 i \, f x + 2 i \, e\right )} + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}\right )^{n} \sqrt{\frac{a}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}{\left (e^{\left (2 i \, f x + 2 i \, e\right )} + 1\right )} e^{\left (-i \, f x - i \, e\right )}}{2 \, a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (d \tan{\left (e + f x \right )}\right )^{n}}{\sqrt{a \left (i \tan{\left (e + f x \right )} + 1\right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (d \tan \left (f x + e\right )\right )^{n}}{\sqrt{i \, a \tan \left (f x + e\right ) + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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